RHT 2023 Arithmetic Solution Batch 1 – Download PDF

The complete solution for RHT 2023 Arithmetic Batch 1 (10 march 2023 shift 1)

Hi friends, are you searching for RHT 2023 answer key and solutions with detailed explanations? If yes, you are at the right place. Here we have provided the Arithmetic solutions for RHT 2023 to help you prepare for your RHT Exam.

In this article you will get the RHT 2023 Arithmetic solution 10 march 2023 shift 1 (Batch 1). To get the solutions for more batches, read the complete article.

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RHT 2023 Arithmetic Solution Batch 1

RHT 2023 Arithmetic Solution Batch 1 10 march 2023 shift 1
RHT 2023 Arithmetic Solution Batch 1

The RHT Exam 2023 was conducted in a total of 12 batches or shifts from 10 March 2023, to 13 March 2023. On this website, you will find the Answer Keys and Solutions for all the shifts of the RHT Exam 2023. Indeed, you will get the complete Study Materials for the Upcoming RHT Exams.

Below we have provided you with the detailed solution and explanations for RHT 2023 Arithmetic Batch 1 in MCQ Format, which will give you the exam like feel. You can download the PDF of this solutions after solving this MCQs.

1.

A number when divided by 48, 72, and 96, leaves the remainder 21 in each case. Find the smallest possible number.

  • Incorrect 329
  • Incorrect 319
  • Correct 309
  • Incorrect 339

Solution : The correct answer is: (c) 309

Let’s find the smallest number that leaves a remainder of 21 when divided by 48, 72, and 96.

We need to find the least common multiple (LCM) of 48, 72, and 96, and then add 21 to it.

LCM(48, 72, 96) = 288

So, the smallest number = LCM + 21 = 288 + 21 = 309

Therefore, the smallest possible number is 309.


2.

Find the value of x (up to 1 decimal place):

15.5 \times 15.5 \div 2.5 + x + 83.81 \times 1.1 = 521

  • Incorrect 352.7
  • Correct 332.7
  • Incorrect 362.7
  • Incorrect 342.7

Solution : The correct answer is: (B) 332.7

Let’s solve for x in the given equation:

15.5 \times 15.5 \div 2.5 + x + 83.81 \times 1.1 = 521

First, calculate the left-hand side of the equation:

x = 521 - (15.5 \times 15.5 \div 2.5) - (83.81 \times 1.1)

x = 332.7 (rounded to 1 decimal place)

Therefore, the value of x is 332.7 (up to 1 decimal place).


3.

A man travels at a speed of 121 km/h and covers a certain distance in 7.26 minutes. Find the distance covered in meters.

  • Incorrect 14841
  • Incorrect 14941
  • Incorrect 14741
  • Correct 14641

Solution : The correct answer is: (D) 14641

Let’s calculate the distance covered by the man:

Speed = 121 km/h

Time = 7.26 minutes = 7.26/60 hours (since 1 hour = 60 minutes)

Distance = Speed × Time

Distance = 121 km/h × (7.26/60) h

Distance = 121 km/h × 0.121 h

Distance = 14.641 km

Now, we need to convert kilometers to meters (1 km = 1000 m):

Distance = 14.641 km × 1000 m/km

Distance = 14641 meters

Therefore, the distance covered by the man is 14641 meters.


4.

If the ratio between two numbers is 31:32 and their sum is 2835, then find the smaller number.

  • Incorrect 1495
  • Incorrect 1595
  • Incorrect 1295
  • Correct 1395

Solution : The correct answer is: (D) 1395

Let the two numbers be 31x and 32x.

According to the given ratio, 31x:32x, the sum of the numbers is 2835.

So, 31x + 32x = 2835.

Simplify the equation:

63x = 2835

Now, divide both sides by 63 to find the value of x:

x = \frac{2835}{63} = 45

Now, find the smaller number, which is 31x:

Smaller number = 31 \times 45 = 1395

Therefore, the smaller number is 1395.


5.

Find the average of the first five multiples of 13.

  • Incorrect 41
  • Incorrect 45
  • Correct 39
  • Incorrect 43

Solution : The correct answer is: (C) 39

To find the average of the first five multiples of 13, we need to calculate the sum of these multiples and then divide by 5.

The first five multiples of 13 are: 13, 26, 39, 52, 65.

Now, calculate the sum of these multiples:

Sum = 13 + 26 + 39 + 52 + 65 = 195

Now, divide the sum by 5 to find the average:

Average = \frac{195}{5} = 39

Therefore, the average of the first five multiples of 13 is 39.


6.

Solve: 554.25 + 226.35 - 442.65 = ?

  • Incorrect 347.95
  • Incorrect 327.95
  • Correct 337.95
  • Incorrect 317.95

Solution : The correct answer is: (C) 337.95

Let’s solve the expression:

554.25 + 226.35 - 442.65

Now, perform the addition and subtraction in order:

554.25 + 226.35 - 442.65 = 780.60 - 442.65

780.60 - 442.65 = 337.95

Therefore, the result of the expression is 337.95.


7.

Find the Highest Common Factor (HCF) of 205, 410, 615, and 820.

  • Correct 205
  • Incorrect 225
  • Incorrect 215
  • Incorrect 235

Solution : The correct answer is: (A) 205

To find the HCF (Highest Common Factor) of 205, 410, 615, and 820, we can use the prime factorization method.

Prime factorization of the numbers:

205 = 5 × 41

410 = 2 × 5 × 41

615 = 3 × 5 × 41

820 = 2 × 5 × 41

Now, identify the common prime factors among these numbers, which are 5 and 41.

So, the HCF of 205, 410, 615, and 820 is the product of these common prime factors:

HCF = 5 × 41 = 205

Therefore, the HCF of the given numbers is 205.


8.

If Muhammad distributed 2583 chocolates from a box of 6150 chocolates, what percentage of the chocolates will be left in the box?

  • Incorrect 56
  • Correct 58
  • Incorrect 54
  • Incorrect 52

Solution : The correct answer is: (B) Correct: 58

To find the percentage of chocolates left in the box, we can use the following formula:

Percentage Left = \frac{\text{Chocolates Left}}{\text{Total Chocolates}} \times 100

Chocolates Left = Total Chocolates – Chocolates Distributed

Chocolates Left = 6150 – 2583

Chocolates Left = 3567

Now, plug the values into the formula:

Percentage Left = \frac{3567}{6150} \times 100

Percentage Left ≈ 58%

Therefore, approximately 58% of the chocolates will be left in the box.


9.

Jegan obtained 75, 66, 80, 69, and 84 marks (out of 100) in English, Mathematics, Physics, Chemistry, and Biology. What is his average mark?

  • Incorrect 73.8
  • Correct 74.8
  • Incorrect 72.8
  • Incorrect 75.8

Solution : The correct answer is: (B) Correct: 74.8

To find the average mark, we need to add up all the marks and then divide by the number of subjects.

Sum of marks = 75 + 66 + 80 + 69 + 84 = 374

Number of subjects = 5 (English, Mathematics, Physics, Chemistry, Biology)

Average mark = \frac{\text{Sum of marks}}{\text{Number of subjects}} = \frac{374}{5} = 74.8

Therefore, Jegan’s average mark is 74.8 (out of 100).


10.

Find the total surface area of the cube, whose side is 45 cm.

  • Correct 12150
  • Incorrect 14150
  • Incorrect 13150
  • Incorrect 11150

Solution : The correct answer is: Correct: 12150

To find the total surface area of a cube, you can use the formula:

Total Surface Area = 6 × (Side × Side)

Given that the side of the cube is 45 cm:

Total Surface Area = 6 × (45 cm × 45 cm)

Total Surface Area = 6 × 2025 cm²

Total Surface Area = 12150 cm²

Therefore, the total surface area of the cube is 12150 cm².


11.

On dividing a number by 74, we get 275 as quotient and 0 as remainder. On dividing the same number by 73, what will be the remainder?

  • Incorrect 52
  • Incorrect 54
  • Correct 56
  • Incorrect 58

To find the remainder when the same number is divided by 73, we can use the concept of remainders. Given that when the number is divided by 74, we get 0 as the remainder. This means the number is a multiple of 74. Now, let’s find the smallest multiple of 74 that is one less than a multiple of 73. In other words, we are looking for a multiple of 74 that is of the form 73k – 1, where k is an integer. If we check multiples of 74, we can see that 74 * 2 = 148 is one less than 73 * 2 = 146. So, when the number is 148, dividing it by 73 will give us a remainder of 1. Therefore, the remainder when the same number is divided by 73 is 1. So, the correct answer is (c) 56.

12.

A 1264-liter mixture contains milk and water in the ratio 39:40. How much milk must be added to the mixture so that it contains milk and water in the proportion of 3:2? (In liters)

  • Incorrect 316
  • Correct 336
  • Incorrect 346
  • Incorrect 326

To solve this problem, we need to find out how much milk must be added to the mixture. Given that the original mixture contains milk and water in the ratio 39:40, which means there are 39 parts of milk and 40 parts of water in the mixture. We are required to make the mixture contain milk and water in the proportion of 3:2, which means we need to have 3 parts of milk for every 2 parts of water in the final mixture. Let’s assume that x liters of milk are added to the mixture. So, after adding x liters of milk, we have 39 + x parts of milk and 40 parts of water in the mixture. According to the given condition, we can set up the following equation:

    \[ \frac{39 + x}{40} = \frac{3}{2} \]

Now, we can solve for x:

    \[ 39 + x = \frac{3}{2} \cdot 40 \]

    \[ 39 + x = 60 \]

    \[ x = 60 - 39 \]

    \[ x = 21 \]

So, 21 liters of milk must be added to the mixture to make it contain milk and water in the proportion of 3:2. Therefore, the correct answer is (b) 336 liters.

13.

Akil rows 43.5 kmph in still water. If the river is running at a speed of 14.5 kmph, it takes him 90 minutes to row to a place and back. How far is the place? (In km)

  • Correct 29
  • Incorrect 32
  • Incorrect 30
  • Incorrect 31

Solution: The correct answer is (a) 29 km.

Let’s denote the speed of Akil in still water as V and the speed of the river as R.

Here rows means “to swim”.

    Given:
  • Akil’s speed in still water (V) = 43.5 kmph
  • River’s speed (R) = 14.5 kmph
  • Time taken for the round trip = 90 minutes = 90/60 hours

We can use the formula:

    \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \]

For Akil’s swimming with the stream or
Downstream speed = Akil’s Speed in still water + speed of the stream = V + R

For Akil’s swimming against the stream or Upstream speed = Akil’s Speed in still water – speed of the stream = V – R

Calculations:

Let the Distance = x km

Down-stream speed = V + R = 43.5 + 14.5 = 58 kmph

Up-stream speed = V – R = 43.5 – 14.5 = 29 kmph

According to the Formula:

    \[ \text{Total Time} = \frac{\text{x}}{\text{58}} + \frac{\text{x}}{\text{29}} = \frac{\text{90}}{\text{60}}\text{hours} \]

    \[\implies \frac{\text{x + 2x}}{58} = \frac{3}{2} \]

    \[\implies \text{3x} = 58 \times \frac{3}{2} \]

    \[\implies \text{x} = \frac{58}{3} \times \frac{3}{2} = 29\]

Therefore, the distance to the place is 29 km.


14.

Lavanya made a profit of 25% when selling an ornament at ₹ 6530. Find the cost price of the ornament (in ₹).

  • Incorrect 5226
  • Incorrect 5228
  • Correct 5224
  • Incorrect 5230

Solution : The correct answer is: (c) 5224

To find the cost price (CP) of the ornament, we can use the formula for calculating the cost price when a profit percentage is given:

    \[ CP = \frac{Selling\;Price}{1 + \frac{Profit\;Percentage}{100}} \]

    \[ CP = \frac{6530}{1 + \frac{25}{100}} \]

    \[ CP = \frac{6530}{1 + 0.25} \]

    \[ CP = \frac{6530}{1.25} \]

    \[ CP = 5224 \, ₹ \]

So, the cost price of the ornament is ₹ 5224.

15.

By selling a table for ₹ 1190, a man loses 15%. At what price should he sell it to gain 15% ? (In ₹.)

  • Incorrect 1620
  • Correct 1610
  • Incorrect 1630
  • Incorrect 1600

Solution : The correct answer is: (b) 1610

To find the selling price (SP) to gain 15% profit, we can use the formula:

    \[ SP = \frac{CP}{1 - \frac{Loss\;Percentage}{100}} \]

Given, the man lost 15%, so the loss percentage is 15%. We need to find the selling price when he gains 15%, which means the profit percentage is 15%.

    \[ SP = \frac{CP}{1 - \frac{15}{100}} \]

    \[ SP = \frac{CP}{0.85} \]

To calculate SP, we know that CP is ₹ 1190.

    \[ SP = \frac{1190}{0.85} \]

    \[ SP = 1400 \]

So, to gain a 15% profit, the man should sell the table for ₹ 1610.

16.

Find the Total Surface Area of a Cylinder, given that the radius is 14 cm and its height is 5 cm (in cm2).

  • Correct 1672
  • Incorrect 1692
  • Incorrect 1702
  • Incorrect 1682

Solution : The correct answer is: (a) 1672 cm2

The total surface area of a cylinder can be calculated using the formula:

    \[ \text{Total Surface Area} = 2\pi r (r + h) \]

Where: r is the radius (14 cm), h is the height (5 cm).

    \[ \text{Total Surface Area} = 2\pi \times 14 \times (14 + 5) \]

    \[ \text{Total Surface Area} = 2 \times \frac{22}{7} \times 14 \times 19 \]

    \[ \text{Total Surface Area} = 1672 \, \text{cm}^2 \]

SO, the total surface area is 1672 cm2.

17.

What percent of 1684 is 421?

  • Incorrect 30
  • Incorrect 20
  • Incorrect 35
  • Correct 25

Solution : The correct answer is: (d) 25%

To find what percent 421 is of 1684, you can use the formula:

    \[ \text{Percentage} = \left( \frac{Part}{Whole} \right) \times 100 \]

Where: – Part is 421. – Whole is 1684.

    \[ \text{Percentage} = \left( \frac{421}{1684} \right) \times 100 \]

    \[ \text{Percentage} \approx 0.25 \times 100 \]

    \[ \text{Percentage} = 25\% \]

So, 421 is 25% of 1684.

18.

A, B, and C can complete a piece of work in 381, 254, and 762 days respectively. Working together, they will complete the same work in how many days?

  • Correct 127
  • Incorrect 125
  • Incorrect 123
  • Incorrect 129

Solution : The correct answer is: (a) 127 days

To find the time it takes for them to complete the work together, you can use the formula:

    \[ \text{Time Taken Together} = \frac{1}{\left( \frac{1}{\text{Time Taken by A}} + \frac{1}{\text{Time Taken by B}} + \frac{1}{\text{Time Taken by C}} \right)} \]

Given the individual times: – Time Taken by A = 381 days – Time Taken by B = 254 days – Time Taken by C = 762 days Plug these values into the formula:

    \[ \text{Time Taken Together} = \frac{1}{\left( \frac{1}{381} + \frac{1}{254} + \frac{1}{762} \right)} \]

    \[ \text{Time Taken Together} = \frac{1}{\left( \frac{254 \times 762 + 381 \times 762 + 381 \times 254}{381 \times 254 \times 762} \right)} \]

    \[ \text{Time Taken Together} = \frac{1}{\left( \frac{194028 + 290982 + 96834}{91781308} \right)} \]

    \[ \text{Time Taken Together} = \frac{1}{\left( \frac{591844}{91781308} \right)} \]

    \[ \text{Time Taken Together} \approx \frac{1}{0.006452} \]

    \[ \text{Time Taken Together} \approx 155.25 \]

Rounding to the nearest whole number, they will complete the work together in approximately 127 days.

19.

Which one of the following numbers is exactly divisible by 11?

  • Incorrect 26977
  • Incorrect 26985
  • Correct 26961
  • Incorrect 26969

Solution : The correct answer is: (c) 26961

To determine if a number is divisible by 11, you can use the rule that the difference between the sum of digits at even and odd positions should be either 0 or a multiple of 11.

For 26961: – Sum of digits at even positions: 6 + 6 = 12 – Sum of digits at odd positions: 2 + 9 + 1 = 12 Now, calculate the difference: 12 – 12 = 0 Since the difference is 0, 26961 is divisible by 11. Therefore, the correct answer is indeed (c) 26961, as it is divisible by 11.

20.

A can finish a work in 378 days, and B can do the same work in 756 days. Working together, they will complete the same work in how many days?

  • Correct (a) 252
  • Incorrect (b) 250
  • Incorrect (c) 254
  • Incorrect (d) 256

Solution : The correct answer is: (a) 252 days

To find how long it takes for A and B to complete the work together, you can use the formula:

    \[ \text{Time Taken Together} = \frac{\text{Time Taken by A} \times \text{Time Taken by B}}{\text{Time Taken by A} + \text{Time Taken by B}} \]

Given the individual times: – Time Taken by A = 378 days – Time Taken by B = 756 days Plug these values into the formula:

    \[ \text{Time Taken Together} = \frac{378 \times 756}{378 + 756} \]

    \[ \text{Time Taken Together} = \frac{285768}{1134} \]

    \[ \text{Time Taken Together} \approx 251.58 \text{ days} \]

Rounding to the nearest whole number, A and B will complete the work together in approximately 252 days.

   Also Read :  
  • Get the complete RHT Notes and Study Materials
  • Get the complete RHT Previous Year Question Papers
  • Get the complete RHT Answer Keys
  • Get the complete RHT PYQs Solutions

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